apply - R: f(x) != sapply(x,f) -- bug or feature? -

March 15, 2015

  & gt; F = function (x) as in. Date (As Character (x), Format = '% Y% M% D') & gt; F (20110606) [1] "2011-06-06" & gt; Sapply (20110606, f) [1] 15131    Why 2 returned values are not the same I need to apply this function to the dates of a long vector, but I sapply I am not getting dates together!   
 
   & gt; Lapli (20110606, f) [[1]] [1] "2011-06-06" & gt; Unlisted (lapply (20110606, f)) [1] 15131     sapply  is not dismissed alone and does not leave the date of doing so  
  & gt; Unclassified (Lapli (20110606, F) [[1]]) [1] 15131 & gt; As a "date" (@ 20110606, F) [1]] [1] "Date"    @USUSA Ulrich said that no need to use application types for interest Is not  
  d> - 20110606 + 0:10 do.call ("c", lapply (d, f))    one possible The method will be "Do not list the list   

 


  

















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